Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 464: 108

Answer

$5-4i$

Work Step by Step

Using $i=\sqrt{-1}$ and the properties of radicals, the given expression, $ 5-\sqrt{-16} ,$ is equivalent to \begin{array}{l}\require{cancel} 5-\sqrt{-1}\cdot\sqrt{16} \\\\= 5-i\sqrt{(4)^2} \\\\= 5-i\cdot4 \\\\= 5-4i .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.