Answer
$\sqrt[3]{25}$
Work Step by Step
To make the denominator of the given expression, $
\dfrac{9}{\sqrt[3]{5}}
,$ a perfect cube, the smallest number to be multiplied to both the numerator and the denominator is$
\sqrt[3]{25}
.$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 446: 93
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