Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 446: 91b

Answer

$\dfrac{y\sqrt{15xy}}{6x^2}$

Work Step by Step

Multiplying the numerator and the denominator of the given expression, $ \dfrac{\sqrt{5y^3}}{\sqrt{12x^3}} ,$ by $ \sqrt{3x} $ results to \begin{array}{l}\require{cancel} \dfrac{\sqrt{5y^3}}{\sqrt{12x^3}}\cdot\dfrac{\sqrt{3x}}{\sqrt{3x}} \\\\= \dfrac{\sqrt{5y^3(3x)}}{\sqrt{12x^3(3x)}} \\\\= \dfrac{\sqrt{15xy^3}}{\sqrt{36x^4}} \\\\= \dfrac{\sqrt{y^2\cdot15xy}}{\sqrt{(6x^2)^2}} \\\\= \dfrac{y\sqrt{15xy}}{6x^2} .\end{array}
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