Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 446: 86

Answer

$y=\left\{ -2, -\dfrac{4}{5} \right\}$

Work Step by Step

Equating each factor to zero (Zero-Product Property), then the values of $y$ that satisfy the given equation, $ (y+2)(5y+4)=0 ,$ are \begin{array}{l}\require{cancel} y+2=0 \\\\ y=-2 ,\\\\\text{OR}\\\\ 5y+4=0 \\\\ 5y=-4 \\\\ y=-\dfrac{4}{5} .\end{array} Hence, $ y=\left\{ -2, -\dfrac{4}{5} \right\} .$
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