Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 446: 88

Answer

$x=\left\{ -1,0,1 \right\}$

Work Step by Step

Factoring the equation and then equating each factor to zero (Zero-Product Property), then the values of $x$ that satisfy the given equation, $ x^3=x ,$ are \begin{array}{l}\require{cancel} x^3-x=0 \\\\ x(x^2-1)=0 \\\\ x(x+1)(x-1)=0 \\\\ x=0 ,\\\\\text{OR}\\\\ x+1=0 \\\\ x=-1 ,\\\\\text{OR}\\\\ x-1=0 \\\\ x=1 .\end{array} Hence, $ x=\left\{ -1,0,1 \right\} .$
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