## Intermediate Algebra (6th Edition)

$\text{approximately } 211.6 \text{ square centimeters}$
Substituting $h=3$ and $r=4$ in the given equation, $A=\pi r\sqrt{r^2+h^2} ,$ results to \begin{array}{l}\require{cancel} A=\pi (6.8)\sqrt{6.8^2+7.2^2} \\ A=6.8\pi\sqrt{46.24+51.84} \\ A=6.8\pi\sqrt{98.08} \\ A\approx211.6 .\end{array} Hence, the lateral surface area, $A,$ is $\text{approximately } 211.6 \text{ square centimeters} .$