Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set: 126a

Answer

$\text{approximately } 3.8 \text{ times}$

Work Step by Step

Substituting $x=3$ in the given function, $ F(x)=0.6\sqrt{49-x^2} ,$ results to \begin{array}{l}\require{cancel} F(x)=0.6\sqrt{49-3^2} \\ F(x)=0.6\sqrt{49-9} \\ F(x)=0.6\sqrt{40} \\ F(x)=0.6\sqrt{4\cdot10} \\ F(x)=0.6\sqrt{(2)^2\cdot10} \\ F(x)=0.6(2)\sqrt{10} \\ F(x)=1.2\sqrt{10} \\ F(x)\approx3.8 .\end{array} Hence, the demand per week, $F(x),$ of an older released DVD is $ \text{approximately } 3.8 \text{ times} .$
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