Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set - Page 434: 127a

Answer

$\text{approximately } 62.8 \text{ centimeters}$

Work Step by Step

Substituting $h=3$ and $r=4$ in the given equation, $ A=\pi r\sqrt{r^2+h^2} ,$ results to \begin{array}{l}\require{cancel} A=\pi (4)\sqrt{4^2+3^2} \\ A=4\pi\sqrt{16+9} \\ A=4\pi\sqrt{25} \\ A=4\pi\sqrt{(5)^2} \\ A=4\pi(5) \\ A=20\pi \\ A\approx62.8 .\end{array} Hence, the lateral surface area, $A,$ is $ \text{approximately } 62.8 \text{ centimeters} .$
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