## Intermediate Algebra (6th Edition)

$\text{approximately } 62.8 \text{ centimeters}$
Substituting $h=3$ and $r=4$ in the given equation, $A=\pi r\sqrt{r^2+h^2} ,$ results to \begin{array}{l}\require{cancel} A=\pi (4)\sqrt{4^2+3^2} \\ A=4\pi\sqrt{16+9} \\ A=4\pi\sqrt{25} \\ A=4\pi\sqrt{(5)^2} \\ A=4\pi(5) \\ A=20\pi \\ A\approx62.8 .\end{array} Hence, the lateral surface area, $A,$ is $\text{approximately } 62.8 \text{ centimeters} .$