Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set - Page 434: 121


$z^{10}\sqrt[3] (z^{2})$

Work Step by Step

$\sqrt[3] (z^{32})=\sqrt[3] (z^{30}\times z^{2})=\sqrt[3] (z^{30})\times \sqrt[3] (z^{2})=z^{10}\sqrt[3] (z^{2})$ We know that $\sqrt[3] (z^{30})=z^{10}$, because $(z^{10})^{3}=z^{10\times3}=z^{30}$.
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