Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 424: 54

Answer

$y^{2}$

Work Step by Step

Using laws of exponents, then, \begin{array}{l} \dfrac{y^{11/3}}{(y^5)^{1/3}} \\\\= \dfrac{y^{\frac{11}{3}}}{y^{\frac{5}{3}}} \\\\= y^{\frac{11}{3}-\frac{5}{3}} \\\\= y^{\frac{6}{3}} \\\\= y^{2} .\end{array}
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