Answer
$b^{\frac{17}{5}}$
Work Step by Step
Using laws of exponents, then,
\begin{align*}
b^{9/5}b^{8/5}
\\\\=
b^{\frac{9}{5}+\frac{8}{5}}
\\\\=
b^{\frac{17}{5}}
.\end{align*}
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.