Answer
$-b$
Work Step by Step
Using laws of exponents, then,
\begin{array}{l}
\dfrac{b^{1/2}b^{3/4}}{-b^{1/4}}
\\\\=
-b^{\frac{1}{2}+\frac{3}{4}-\frac{1}{4}}
\\\\=
-b^{\frac{2}{4}+\frac{3}{4}-\frac{1}{4}}
\\\\=
-b^{\frac{4}{4}}
\\\\=
-b
.\end{array}