Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Sections 6.1-6.5 - Integrated Review - Expressions and Equations Containing Rational Expressions - Page 380: 9

Answer

$x=-5$

Work Step by Step

Expressing the terms of the given equation, $ \dfrac{2}{x^2-4}=\dfrac{1}{x+2}-\dfrac{3}{x-2} ,$ in factored form results to \begin{array}{l}\require{cancel} \dfrac{2}{(x+2)(x-2)}=\dfrac{1}{x+2}-\dfrac{3}{x-2} .\end{array} Multiplying both sides by the $LCD= (x+2)(x-2) $, then the solution to the equation above is \begin{array}{l} 1(2)=(x-2)(1)-(x+2)(3) \\\\ 2=x-2-3x-6 \\\\ -x+3x=-2-6-2 \\\\ 2x=-10 \\\\ x=-\dfrac{10}{2} \\\\ x=-5 .\end{array}
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