Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Sections 6.1-6.5 - Integrated Review - Expressions and Equations Containing Rational Expressions - Page 380: 25

Answer

$a=-1$

Work Step by Step

Multiplying both sides by the $LCD= a $, then the solution to the given equation, $ \dfrac{3}{a}-5=\dfrac{7}{a}-1 ,$ is \begin{array}{l} 1(3)-a(5)=1(7)-a(1) \\\\ 3-5a=7-a \\\\ -5a+a=7-3 \\\\ -4a=4 \\\\ a=\dfrac{4}{-4} \\\\ a=-1 .\end{array}
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