Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Sections 6.1-6.5 - Integrated Review - Expressions and Equations Containing Rational Expressions - Page 380: 7

Answer

$x=4$

Work Step by Step

By cross-multiplication, the solution to the given equation, $ \dfrac{4}{x+2}=\dfrac{2}{x-1} ,$ is \begin{array}{l} 4(x-1)=2(x+2) \\\\ 4x-4=2x+4 \\\\ 4x-2x=4+4 \\\\ 2x=8 \\\\ x=\dfrac{8}{2} \\\\ x=4 .\end{array}
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