Answer
see graph
Work Step by Step
With $k=3,$ then the given variation model, $y=\dfrac{k}{x},$ becomes
\begin{array}{l}\require{cancel}
y=\dfrac{3}{x}
.\end{array}
If $x=\dfrac{1}{4},$ then
\begin{array}{l}\require{cancel}
y=\dfrac{3}{1/4}
\\\\
y=3\div\dfrac{1}{4}
\\\\
y=3\cdot\dfrac{4}{1}
\\\\
y=12
.\end{array}
If $x=\dfrac{1}{2},$ then
\begin{array}{l}\require{cancel}
y=\dfrac{3}{1/2}
\\\\
y=3\div\dfrac{1}{2}
\\\\
y=3\cdot\dfrac{2}{1}
\\\\
y=6
.\end{array}
If $x=1,$ then
\begin{array}{l}\require{cancel}
y=\dfrac{3}{1}
\\\\
y=3
.\end{array}
If $x=2,$ then
\begin{array}{l}\require{cancel}
y=\dfrac{3}{2}
.\end{array}
If $x=4,$ then
\begin{array}{l}\require{cancel}
y=\dfrac{3}{4}
.\end{array}
The completed table and the corresponding graph is shown above.