Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.7 - Variation and Problem Solving - Exercise Set: 66



Work Step by Step

We know that $\sqrt (\frac{25}{121})=\frac{5}{11}$, because $(\frac{5}{11})^{2}=\frac{5}{11}\times\frac{5}{11}=\frac{5\times5}{11\times11}=\frac{25}{121}$.
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