Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.7 - Variation and Problem Solving - Exercise Set: 65



Work Step by Step

We know that $\sqrt (\frac{4}{9})=\frac{2}{3}$, because $(\frac{2}{3})^{2}=\frac{2}{3}\times\frac{2}{3}=\frac{2\times2}{3\times3}=\frac{4}{9}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.