Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.7 - Variation and Problem Solving - Exercise Set: 64



Work Step by Step

We know that $\sqrt (\frac{1}{25})=\frac{1}{5}$, because $(\frac{1}{5})^{2}=\frac{1}{5}\times\frac{1}{5}=\frac{1\times1}{5\times5}=\frac{1}{25}$.
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