Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 78

Answer

$6.0\times10^{-5}$

Work Step by Step

Using laws of exponents, the given expression simplifies to \begin{align*} & \dfrac{0.0003\times0.0024}{0.0006\times20} \\\\&= \dfrac{3.0\times10^{-4}\times2.4\times10^{-3}}{6.0\times10^{-4}\times20} \\\\&= (3.0\times2.4\div6\div20)(10^{-4}\times10^{-3}\div10^{-4}) \\\\&= 0.06\times10^{-4+(-3)-(-4)} \\\\&= 0.06\times10^{-3} \\\\&= 6.0\times10^{-5} .\end{align*}
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