Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 71

Answer

$8.0\times10^{15}$

Work Step by Step

Using laws of exponents, the given expression simplifies to \begin{align*} & (2\times10^{5})^3 \\\\&= 2^3\times10^{5(3)} \\\\&= 8.0\times10^{15} .\end{align*}
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