Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 24

Answer

$\dfrac{8}{x^{12}y^{18}} $

Work Step by Step

Using laws of exponents, the given expression simpifies to \begin{align*} & \left( \dfrac{5x^7y^4}{10x^3y^{-2}} \right)^{-3} \\\\&= \left( \dfrac{x^{7-3}y^{4-(-2)}}{2} \right)^{-3} \\\\&= \left( \dfrac{x^{4}y^{6}}{2} \right)^{-3} \\\\&= \dfrac{x^{4(-3)}y^{6(-3)}}{2^{-3}} \\\\&= \dfrac{x^{-12}y^{-18}}{2^{-3}} \\\\&= \dfrac{2^{3}}{x^{12}y^{18}} \\\\&= \dfrac{8}{x^{12}y^{18}} .\end{align*}
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