Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set: 38

Answer

$7^{6}a^{2}b^{4}$

Work Step by Step

$(\frac{7^{-3}}{ab^{2}})^{-2}$ Using $\frac{1}{a^{n}}= a^{-n}$ $= (7^{-3}a^{-1}b^{-2})^{-2}$ $= (7^{-3})^{-2}(a^{-1})^{-2}(b^{-2})^{-2}$ Using $(a^{m})^{n} =a^{m \times n} $ $=7^{6}a^{2}b^{4}$
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