Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 330: 79


8$x^{2}$(2x - 3)

Work Step by Step

The GCF of 16 and 24 is 8, and the GCF of $x^{3}$ and $x^{2}$ is $x^{2}$. Therefore, the GCF is 8$x^{2}$. Then factor out the GCF by dividing each figure to get 8$x^{2}$(2x - 3).
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