Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 330: 38



Work Step by Step

Using scientific notation and the laws of exponents, the given expression, $ \dfrac{(-0.00017)(0.00039)}{3000} $, simplifies to \begin{array}{l} \dfrac{(-1.7\times10^{-4})(3.9\times10^{-4})}{3\times10^{3}} \\\\= (-1.7)(3.9)\div3\times10^{-4+(-4)-3} \\\\= -2.21\times10^{-11} .\end{array}
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