## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 5 - Review - Page 330: 48

#### Answer

4$x^{3}$ + 4$x^{2}$ + 16xy - 9x + 18

#### Work Step by Step

(9xy + 4$x^{2}$ + 18) + (7xy - 4$x^{3}$ - 9x) = -4$x^{3}$ + 4$x^{2}$ + (9xy + 7xy) - 9x + 18 = 4$x^{3}$ + 4$x^{2}$ + 16xy - 9x + 18

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