Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review: 76

Answer

The area of the square is $121y^2+198y+81$ square units.

Work Step by Step

RECALL: The area of a square is given by the formula $A=s^2$ where s = side length. The square has $s=11y+9$. Use the formula above to have: $\\A=(11y+9)^2$ RECALL: $(a+b)^2=a^2+2ab+b^2$ Use the formula above with $a=11y$ and $b=9$ to have: $\\A=(11y)^2+2(11y)(9)+9^2 \\A=121y^2+198y+81$
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