Intermediate Algebra (6th Edition)

The solution is $y=0$
$6(y-4)=3(y-8)$ Evaluate the products on both sides: $6y-24=3y-24$ Take $3y$ to the left side and $24$ to the right side: $6y-3y=-24+24$ $3y=0$ Take $3$ to divide the right side: $y=\dfrac{0}{3}$ $y=0$