Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Sections 2.1-2.4 - Integrated Review - Linear Equations and Inequalities - Page 88: 5


The solution is $y=0$

Work Step by Step

$6(y-4)=3(y-8)$ Evaluate the products on both sides: $6y-24=3y-24$ Take $3y$ to the left side and $24$ to the right side: $6y-3y=-24+24$ $3y=0$ Take $3$ to divide the right side: $y=\dfrac{0}{3}$ $y=0$
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