Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Sections 2.1-2.4 - Integrated Review - Linear Equations and Inequalities - Page 88: 24

Answer

$y=\frac{9}{13}$

Work Step by Step

$\frac{y}{3}+\frac{y}{5}=\frac{y+3}{10}$ Mutiply both sides by 30, the least common multiple, to eliminate fractions. $30(\frac{y}{3})+30(\frac{y}{5})=30(\frac{y+3}{10})$ $10y+6y=3(y+3)$ Combine like terms and apply the distributive property. $16y=3y+9$ Subtract 3y from both sides. $16y-3y=3y+9-3y$ $13y=9$ Divide both sides by 13. $13y\div13=9\div13$ $y=\frac{9}{13}$
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