Answer
$[-\frac{3}{5},\infty)$
Work Step by Step
$\frac{-5x+11}{2}\leq7$
Solve for x.
Multiply both sides by 2.
$\frac{-5x+11}{2}\times2\leq7\times2$
$-5x+11\leq14$
Subtract 11 from both sides.
$-5x+11-11\leq14-11$
$-5x\leq3$
Divide both sides by -5. When dividing by a negative you must reverse the inequality sign.
$-5x\div-5\geq3\div-5$
$x\geq -\frac{3}{5}$
In interval notation this is written as
$[-\frac{3}{5},\infty)$
where [ indicates that the solution set for x includes $-\frac{3}{5}$.
