Answer
$(-\infty,-\frac{1}{6}]$
Work Step by Step
$-3x\geq\frac{1}{2}$
Solve for x.
Mutiply each sides by -\frac{1}{3}; the negative requires you to reverse the inequality sign.
$-3x\times-\frac{1}{3}\leq\frac{1}{2}\times-\frac{1}{3}$
$x\leq-\frac{1}{6}$
This is written in interval notation as
$(-\infty,-\frac{1}{6}]$
where ] indicates that $-\frac{1}{6}$ is included in the solution set for x.
