Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.4 - Linear Inequalities and Problem Solving - Exercise Set: 57

Answer

(-$\infty$, 9)

Work Step by Step

0.4( 4x - 3 ) $\lt$ 1.2( x + 2 ) $\frac{4}{10}$( 4x ) - $\frac{4}{10}$( 3 ) $\lt$ $\frac{12}{10}$( x ) + $\frac{12}{10}$( 2 ) $\frac{8}{5}$x - $\frac{6}{5}$ $\lt$ $\frac{6}{5}$x + $\frac{12}{5}$ 8x - 6 $\lt$ 6x + 12 2x $\lt$ 18 x $\lt$ 9 In interval notation, the solution set is (-$\infty$, 9)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.