## Intermediate Algebra (6th Edition)

$(-∞,\frac{-35}{6})$
$-3(2x-1) \lt -4[2+3(x+2)]$ Applying distributive property, $-6x+3 \lt -4[2+3x+6]$ $-6x+3 \lt -4[8+3x]$ $-6x+3 \lt -32-12x$ Add $-3$ on both sides. $-6x+3 -3 \lt -32-12x -3$ $-6x \lt -35-12x$ Add $12x$ on both sides. $-6x+12x \lt -35-12x +12x$ $6x \lt -35$ Divide by 6 on both sides. $x \lt \frac{-35}{6}$ In Interval notation : $(-∞,\frac{-35}{6})$