Answer
[$\frac{8}{3}$, infinity)
Work Step by Step
Original equation
5(x+4)$\leq$4(2x+3)
Distribute
5x+20$\leq$8x+12
Subtract 8x and 20 from both sides
-3x$\leq$-8
DIvide both sides by -3
x$\geq$$\frac{8}{3}$
Convert to interval notation
[$\frac{8}{3}$, infinity)
