Answer
(-$\infty$, -8)
Work Step by Step
0.2( 8x - 2 ) $\lt$ 1.2( x - 3 )
$\frac{2}{10}$( 8x ) - $\frac{2}{10}$( 2 ) $\lt$ $\frac{12}{10}$( x ) - $\frac{12}{10}$( 3 )
2( 8x ) - 2( 2 ) $\lt$ 12( x ) - 12( 3 )
16x - 4 $\lt$ 12x - 36
4x $\lt$ -32
x $\lt$ -8
In interval notation, the solution set is (-$\infty$, -8)