## Intermediate Algebra (6th Edition)

(-$\infty$, -8)
0.2( 8x - 2 ) $\lt$ 1.2( x - 3 ) $\frac{2}{10}$( 8x ) - $\frac{2}{10}$( 2 ) $\lt$ $\frac{12}{10}$( x ) - $\frac{12}{10}$( 3 ) 2( 8x ) - 2( 2 ) $\lt$ 12( x ) - 12( 3 ) 16x - 4 $\lt$ 12x - 36 4x $\lt$ -32 x $\lt$ -8 In interval notation, the solution set is (-$\infty$, -8)