Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.4 - Linear Inequalities and Problem Solving - Exercise Set: 58

Answer

(-$\infty$, -8)

Work Step by Step

0.2( 8x - 2 ) $\lt$ 1.2( x - 3 ) $\frac{2}{10}$( 8x ) - $\frac{2}{10}$( 2 ) $\lt$ $\frac{12}{10}$( x ) - $\frac{12}{10}$( 3 ) 2( 8x ) - 2( 2 ) $\lt$ 12( x ) - 12( 3 ) 16x - 4 $\lt$ 12x - 36 4x $\lt$ -32 x $\lt$ -8 In interval notation, the solution set is (-$\infty$, -8)
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