Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Cumulative Review - Page 115: 41


$p=-2$ and $p=2$

Work Step by Step

We are given that $|p|=2$. The solution set will be all values of p that have an absolute value of 2 (or all values of p that are exactly 2 units away from 0 on the number line). -2 and 2 are both 2 units from 0 on the number line, so $p= -2$ and $p=2$. $|-2|=2$ and $|2|=2$
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