Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Cumulative Review - Page 115: 36



Work Step by Step

We are given that $x+3\leq1$ or $3x-1\lt8$. Therefore, a solution for x will only need to satisfy at least one of the inequalities. First, we can solve $x+3\leq1$ Subtract 3 from both sides. $x\leq-2$ Next, we can solve $3x-1\lt8$ Add 1 to both sides. $3x\lt9$ Divide both sides by 3. $x\lt3$ Any number that is less than or equal to -2 will also be less than 3. Therefore, the solution set is any number that is less than 3.
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