Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Cumulative Review - Page 115: 21


23, 49, and 92

Work Step by Step

We are give that the second number is 3 more than twice the first number. So, we assume the first number is x. The second number is three more than two times x, or 3+2x. The third number is four times the first number, or 4x. $x+(3+2x)+4x=164$ $7x+3=164$ $7x=161$ $x=23$ So the numbers are: $23$ $3+2\times23=49$ $4\times23=92$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.