Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Cumulative Review - Page 115: 39



Work Step by Step

We are given that $-2x-5\lt-3$ or $6x\lt0$. Therefore, any solutions must only satisfy at least one of the inequalities. We can first solve $-2x-5\lt-3$ Add 5 to both sides. $-2x\lt2$ Divide both sides by -2 (which will reverse the inequality sign) $x\gt-1$ Next, we can solve $6x\lt0$ Divide both sides by 6. $x\lt0$ Therefore, the solution set consists of all numbers that are greater than -1 or less than 0, which is the set of all real numbers.
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