Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Test - Page 669: 18

Answer

$14/33$

Work Step by Step

$S_∞ = .4242424242424242$ $.4242424242424242424242 = 42/100 + 42/10000 + 42/1000000 + 42/100000000 + . . . $ The first terms is $42/100$ and the common ratio is $1/100$ $S_∞ = a_1/(1-r)$ $S_∞ = 42/100 /(1-1/100)$ $S_∞ = 42/100 / 99/100$ $S_∞ = 42/99$ $42/99 = 14*3/33*3$ $42/99 = 14/33$
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