Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Test - Page 669: 2

Answer

$a_{80}= 247$

Work Step by Step

$a_{n} = 10+3(n-1)$ $a_{80} = 10+3(80-1)$ $a_{80} = 10+3(79)$ $a_{80} = 10+237$ $a_{80} = 247$
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