Answer
First five terms of the sequence is $\frac{-1}{5},\frac{1}{6},\frac{-1}{7},\frac{1}{8},\frac{-1}{9}$
Work Step by Step
$a_{n} = \frac{(-1)^{n}}{n+4}$
$a_{1} = \frac{(-1)^{1}}{1+4} = \frac{-1}{5}$
$a_{2} = \frac{(-1)^{2}}{2+4} = \frac{1}{6} $
$a_{3} = \frac{(-1)^{3}}{3+4} = \frac{-1}{7}$
$a_{4} = \frac{(-1)^{4}}{4+4} = \frac{1}{8}$
$a_{5} = \frac{(-1)^{5}}{5+4} = \frac{-1}{9}$
