Answer
$\frac{107}{105}$
Work Step by Step
We sum from i = low bound to i = high bound.
$\frac{2}{2+3} + \frac{2}{3+3} + \frac{2}{4+3} = \frac{2}{5} + \frac{2}{6} + \frac{2}{7} = \frac{84}{210} + \frac{70}{210} + \frac{60}{210} = \frac{214}{210} = \frac{107}{105}$
