Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.3 - Series - Exercise Set - Page 651: 14

Answer

$2$

Work Step by Step

We sum from i = low bound to i = high bound. $2(2-3) + 3(3-3) + 4(4-3) = 2(-1) + 3(0) + 4(1) = -2 + 0 + 4 = 2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.