Answer
$20$
Work Step by Step
We sum from i = low bound to i = high bound.
$(2^2-3) + (3^2-3) + (4^2-3) = (4-3) + (9-3) + (16-3) = 1 + 6 + 13 = 20$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 11 - Section 11.3 - Series - Exercise Set - Page 651: 5
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