Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.3 - Series - Exercise Set - Page 651: 35

Answer

$-20$

Work Step by Step

Given that $ a_n=-2n $ then the first 4 terms are \begin{array}{l} a_1=-2(1)\\ a_1=-2 ,\\\\ a_2=-2(2)\\ a_2=-4 ,\\\\ a_3=-2(3)\\ a_3=-6 ,\\\\ a_4=-2(4)\\ a_4=-8 .\end{array} Hence, the sum is $ -2-4-6-8 = -20 .$
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