Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.2 - Arithmetic and Geometric Sequences - Exercise Set - Page 647: 56

Answer

The general term $a_n$ of the given sequence is given by the formula: $a_n =15 + 5(n-1)$ After 7 weeks, her riding time would be $45$ minutes. She will have a 1-hour riding time after 10 weeks. Refer to the step-by-step part for the computations/solutions.

Work Step by Step

The given arithmetic sequence has $a_1 = 15$ minutes and a common difference $d=5$. RECALL: The $n^{th}$ term ($a_n$) of an arithmetic sequence is given by the formula $a_n=a_1 +d(n-1)$ where $a_1$ is the first term and $d$ is the common difference. Thus, the general term $a_n$ of the given sequence is given by the formula: $a_n = a_1 +d(n-1) \\a_n=15 + 5(n-1)$ Thus, after 7 weeks, her riding time would be: $a_{7} = a_1 + d(7-1) \\a_{7}=15+ 5(7-1) \\a_{7}=15+5(6) \\a_{7}=15+30 \\a_{7}=45$ Note that $1$ hour = $60$ minutes. Thus, to find the number of weeks it will take for her to reach a 1-hour riding time, set $a_n=60$ and solve for $n$: $a_n=15+5(n-1) \\60=15+5(n-1) \\60-15=5(n-1) \\45=5(n-1) \\\frac{45}{5} = \frac{5(n-1)}{5} \\9=n-1 \\9+1=n \\10=n$ Therefore, it she will have a 1-hour riding time after 10 weeks.
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