Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.2 - Arithmetic and Geometric Sequences - Exercise Set: 63

Answer

$\frac{907}{495}$

Work Step by Step

$\frac{8-1}{8+1} + \frac{8-2}{8+2} +\frac{8-3}{8+3}$ $= \frac{7}{9} + \frac{6}{10} + \frac{5}{11}$ Taking LCD, $= \frac{770+594+450}{990}$ $= \frac{1814}{990}$ $=\frac{907}{495}$
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