Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.2 - Arithmetic and Geometric Sequences - Exercise Set - Page 647: 62

Answer

$\dfrac{11}{24}$

Work Step by Step

The expression $ \dfrac{1}{4(1)}+\dfrac{1}{4(2)}+\dfrac{1}{4(3)} $ evaluates to \begin{array}{l} \dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{12} \\\\= \dfrac{6(1)+3(1)+2(1)}{24} \\\\= \dfrac{6+9+2}{24} \\\\= \dfrac{11}{24} .\end{array}
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