Answer
$a_{n}=6(3)^{n-1}$
Work Step by Step
Given,
$a_{1}=6$
$r = 3$
Substituting $a_{1}$ and $r$ in
$a_{n}= a_{1}(r)^{n-1}$
we get,
$a_{n}=6(3)^{n-1}$
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